Question

If the equation for a transverse wave is y = A sin2π {(1/T) – (x/λ)}, then for what wavelength will the maximum velocity of the particle be double the wave velocity? 

(A) (πA/4) 

(B) (πA/2) 

(C) πA

(D) 2πA

Answer 1

The correct option (C) πA  

Explanation:

maximum velocity of a particle = Aω

wave velocity = fλ

given: max velocity = 2 × wave velocity

∴ Aω = 2fλ

∴ A × 2πf  = 2fλ ------ ω = 2πf

∴ Aπ = λ

 λ = πA