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Find the maximum and minimum values of the function \[ f(x)=x^{3}-9 x^{2}+24 x \].

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\(f(x) = x^3 - 9x^2 + 24x\)

\(f'(x) = 3x^2 - 18x + 24\)

\(f'(x) = 0 \)

⇒ \(3x^2 - 18 x + 24 = 0\)

⇒ \(x^2 - 6x + 8 = 0\)

⇒ \((x -2) (x -4) = 0\)

⇒ \(x = 2\;or\;x = 4\)

\(f''(x) = 6x - 18\)

\(f''(2) = 12 - 18 < 0\)

\(f''(4) = 24 - 18 > 0\)

\(\therefore x = 2 \) is point of maxima and \(x = 4\) is point of minima.

Local maximum value \(= f(2) \)

\(= 8 - 36 + 48 \)

\(= 20\)

Local minimum value \(= f(4) \)

\(= 64 - 144 + 96 \)

\(= 160 - 144\)

\(= 16\)

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