Question

One mole of a symmetrical alkene on ozonolysis gives two moles of an aldehyde having molecular mass 44 u. The alkene is:

(a) 2 – butene
(b) ethene
(c) propene
(d) 1 – butene

Answer 1

(a) 2 – butene

The aldehyde with molecular mass 44 u is CH₃CHO (acetaldehyde). Therefore the symmetrical alkene is 2 – butene.