Question

600 mL of 0.04 M HCl is mixed with 400 mL of 0.02 M H₂SO₄. Find out the pH of resulting solution (Nearest integer).

Answer 1

m moles of H⁺ from HCl = 0.04 × 600 = 24 

m moles of H⁺ from H₂SO₄ = 0.02 × 2 × 400 = 16

Total m moles of H⁺ = 24 + 16 = 40

Final volume of solution = 1000 mL

\(x = [H^+] = \frac{40}{1000} = 0.04 M\)

pH = – log 0.04 = 1.4