Question

2.52 gm of glucose dissolved in 30 gm of water calculate molality.

Answer 1

Molecular weight of glucose = 180 g/mol

\(\therefore \) Number of moles of glucose = \(\frac{2.52}{180}\) = 0.014 mol

As we know, 

Molality = \(\frac{\text{Number of moles of solute}}{\text{1 kg of solvents}}\)

\(\therefore \) Molality of glucose = \(\frac{0.014}{30} \times 1000 = 0.47\)

\(\therefore \) Molality of glucose is 0.47m.