Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.3k views
in Chemistry by (69.2k points)

The reaction of alkyl chloride with aqueous KOH leads to the formation of alcohols but in presence of alcoholic KOH, alkenes are major products. Explain. 

1 Answer

+1 vote
by (59.7k points)
selected by
 
Best answer

In aqueous medium, KOH ionises readily to form OH ions which behave as a powerful nucleophile and cause nucleophilic substitution. These OH ions being highly hydrated in aqueous medium, cannot abstract a proton (H+) form β-carbon. Hence elimination does not take place. But in alcoholic medium the ionisation of the base (KOH) is poor. So OH ions behave as weak nucleophile and the substitution is chacked. Actually KOH in presence of alcoholic medium gives E2 elimination reaction to form alkene.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...