If the lines x-1/2 = y-2/2 = z+3/1 and

Question

If the lines \(\frac{x-1}{2}=\frac{y-2}{2}=\frac{z+3}{1}\) and \(\frac{x-a}{2}=\frac{y+2}{3}=\frac{z-3}{1}\) intersects at the point P, then the distance of the point P from the plane z = a is

(1)16 

(2) 28 

(3)10 

(4) 22

Answer 1

Correct option is (2) 28 

Distance of P from z = –9 is 28