Question

Construct a triangle ABC with sides 3 cm, 4 cm and 5 cm. Now, construct another triangle whose sides 4/5 times the corresponding sides of ∆ABC.

Answer 1

Given a triangle ABC, we required to construct a triangle whose sides are 4/5 times the corresponding sides of ∆ABC.

Steps of Construction:

• Draw a line segment BC = 4 cm.
• With B as centre and radius 3 cm draw and arc.
• With C as centre and radius 5 cm draw another are to intersect the previous arc at A.
• Join AB and AC to get AABC.
• Draw any ray BX making an acute angle with BC on the side opposite to the vertex A.
• Along BX mark 5 points B₁, B₂, B₃, B₄ and B₅ such that BB₁ = B₁B₂ = B₂B₃ = B₃B₄ = B₄B₅
• Join B₅C.
• From B₄ draw B₄C’||B₅C meeting BC at C.
• From C’ draw C’ A’ || CA meeting BA at A’. Then A’ BC’ is required triangle, each of whose side is 4/5 of corresponding sides of ∆ABC.