Question

In a Young’s double slit experiment, the intensities at two points, for the path difference λ/4 and λ/3 (λ being the wavelength of light used) are I₁ and I₂ respectively. If I₀ denotes the intensity produced by each one of the individual slits, then \(\frac{I_1+I_2}{I_0}\) = .....

Answer 1

As we know, resultant intensity is given by,

I = 4I₀ cos²\(\frac {\triangle \phi}{2}\) and phase difference can be written as \(\triangle \phi =\frac {2\pi }{\lambda} \triangle \chi.\)

For first case:

For second case:

Therefore, required value of \(\frac {I_1 +I_2}{I_0} = 3\)

Answer 2

Correct answer is 3