Question

The energy of an electron in n^th orbit of hychogen is [(– 13.6) / n²]eV. energy required to exite the electron form the first orbit 4^th orbit is

(A) 13.6 

(B) 3.4 eV

(C) 12.75 eV

(D) 1.5 eV

Answer 1

The correct option is (C) 12.75 eV.

Explanation:

E_n = [(– 13.6) / n²] eV

n = 1 to n = 4

hence  ΔE = E₄ – E₁ = –13.6[(1 / 4²) – (1 / 1²)] = 12.75 eV.