Let \(A = \begin{bmatrix} \frac 1{\sqrt{10}}&\frac 3{\sqrt{10}}\\\frac {-3}{\sqrt{10}}&\frac 1{\sqrt{10}}\end{bmatrix}\) and \(B = \begin{bmatrix} 1&-i\\0&1\end{bmatrix}\), where i = √-1. If M = ATBA, then the inverse of the matrix AM2023AT is
(1) \(\begin{bmatrix}1&{-2023i}\\0&1\end{bmatrix}\)
(2) \(\begin{bmatrix}1&0\\{-2023i}&1\end{bmatrix}\)
(3) \(\begin{bmatrix}1&0\\{2023i}&1\end{bmatrix}\)
(4) \(\begin{bmatrix}1&{2023i}\\0&1\end{bmatrix}\)