Since the alkyl halide is 3°, (f-butyl chloride) and C2H5ONa is strong base, therefore, elimination occurs to form 2-methylprop-l-ene.
![](https://www.sarthaks.com/?qa=blob&qa_blobid=8328767447226910845)
To prepare 1-butyl ethyl ether, the alkyl halide should be 1°, i.e., chloroethane and the nucleophile should be sodium f-butoxide.
![](https://www.sarthaks.com/?qa=blob&qa_blobid=5958306610293480525)