Given,
y = 5 sin(80πt - 0.5πx)
Comparing equation
y = A sin (ωt - kx)
(i) Amplitude A = 5m
(ii) \(k=\frac{2\pi}{λ}\)
\(λ=\frac{2\pi}{k}\)
\(λ=\frac{2\pi0}{0.5}\)
λ = 4 A°
(iii) ω = 2πv
v = \(\frac{ω}{2\pi}\)
v = \(\frac{80\pi}{2\pi}\)
v = 40 Hz
(iv) \(T=\frac{2\pi}{ω}⇒\frac{2\pi}{80\pi}\)
\(⇒ T=\frac{1}{40}sec\)