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Given that √3 is an irrational number. Prove that (2 + √3) is an irrational number.

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Let us assume, that (2 + √3) is a rational, it can be expressed in the form of a/b, where a and b are coprime positive integers and b ≠ 0.

∴ 2 + √3 = a/b

(∵ HCF of a and b is 1)

⇒ a/b = √2

⇒ a−2b/b = √3

a−2b/b = rational number

(∵ a and b are positive integers) Thus, from eqn. (i) is a rational number.
But this contradicts the fact that is an irrational number. So, our assumption that 2 + √3 is a rational number, is wrong.

Hence, (2 + √3) is an irrational number.

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