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Propose a suitable chemical structure of the organic compounds using the following NMR data and molecular formula

(1) Molecular formula : C10H14

1H (d) ppm : 3H doublet (1.2), 1H sextet (2.5), 2H quintet (1.6), 3H triplet (0.8) and 5H singlet (7.27)

(2) Molecular formula : C9H12

1H (d) ppm : 6H doublet (1.3), 1H septet (3.2), 5H singlet (7.27).​​​

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(1) Double bond equivalent of C10H14 = 4

5 Ha = 7.27 ppm (singlet)

1 Hb = 2.5 ppm (sextet)

3 Hc = 1.2 ppm (doublet)

2 Hd = 1.6 ppm (quintet)

3 He = 0.8 ppm (triplet)

(2) Double bond equivalent of C9H12 = 4

6 Ha = 1.3 (doublet)

1 Hb = 3.2 (septet)

5 Hc = 7.27 (singlet)

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