Question

A photon of energy 1 MeV suffers compton scattering at angle of 60°. Find speed of recoil electron.

Answer 1

We know that,

λ^' - λ = \(\frac{h}{m_oc}\) (1 - cosΦ)

λ^' - λ = \(\frac{6.626\times10^{-34}}{9.1\times10^{-31}\times3\times10^8}\) (1 - cos 60°)

= \(\frac{6.626\times10^{-34}}{9.1\times10^{-31}\times3\times10^8}\) (\(1-\frac{1}{2}\))

= \(\frac{6.626\times10^{-34}}{27.3\times10^{-23}}\) x \(\frac{1}{2}\)

= \(\frac{6.626\times10^{-11}}{54.6}\)

λ^' - λ = 0.121 x 10^-11 m

\(p = \frac{h}{λ }\)

mv = \(\frac{h}{λ }\)

v = \(\frac{h}{λm }\)

v = \(\frac{6.626\times10^{-34}}{0.121\times10^{-11}\times9.1\times10^{-31}}\)

v = \(\frac{6.626\times10^{-34}}{1.101\times10^{-42}}\)

v = 6.0181 x 10⁸ m/sec