We know that,
λ' - λ = \(\frac{h}{m_oc}\) (1 - cosΦ)
λ' - λ = \(\frac{6.626\times10^{-34}}{9.1\times10^{-31}\times3\times10^8}\) (1 - cos 60°)
= \(\frac{6.626\times10^{-34}}{9.1\times10^{-31}\times3\times10^8}\) (\(1-\frac{1}{2}\))
= \(\frac{6.626\times10^{-34}}{27.3\times10^{-23}}\) x \(\frac{1}{2}\)
= \(\frac{6.626\times10^{-11}}{54.6}\)
λ' - λ = 0.121 x 10-11 m
\(p = \frac{h}{λ }\)
mv = \(\frac{h}{λ }\)
v = \(\frac{h}{λm }\)
v = \(\frac{6.626\times10^{-34}}{0.121\times10^{-11}\times9.1\times10^{-31}}\)
v = \(\frac{6.626\times10^{-34}}{1.101\times10^{-42}}\)
v = 6.0181 x 108 m/sec