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A user wants to upload a text document at the rate of 10 pages per 20 second.

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A user wants to upload a text document at the rate of 10 pages per 20 second. What will be the required data rate of the channel? (Assume that 1 page contains 1600 characters and each character is of 8 bits).

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Required data rate = \(\frac{(10\times1600\times8)}{20}\)

= 6400 bps = 6.25 kbps

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