Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
260 views
in Electromagnetic induction and alternating currents by (984 points)
closed by

Consider a long solenoid of radius R which has n turns per unit length. A time dependent current I = I0sin ωt flows in solenoid, magnitude of electric field at a perpendicular distance r < R, from the axis of symmetry of solenoid is found to be E = α/4ωµ0 nI0r cosωt, where α is pure number and µ0 is permability of free space. Find α.

1 Answer

+1 vote
by (48.9k points)
selected by
 
Best answer

Magnetic flux inside solenoid = \(\mu_0ni\)

\(\phi = B.A\)

\(\phi = \mu_0NI\pi r^2\)    \(0\le r\le R\)

\(\frac{-d\phi}{dt} = \phi E.dl\)

\(\mu_o N\pi r^2 \frac{dI}{dt} = E. 2\pi r\)

\(E = \frac{\mu_0Nr}{2} \frac{dI}{dt}\)

\(I = I_0\sin \omega t\)

\(E = \frac{\mu _0Nr}2 I_0\omega \,\cos\omega t\)

For \(r = \frac R2\)

\(E = \mu _0 NI_0 \omega \frac R4 \cos (\omega t)\)

Related questions

0 votes
1 answer
0 votes
0 answers
0 votes
1 answer
0 votes
1 answer
0 votes
1 answer

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...