√2x + √3y = 0 ------- (1)
√3x - √8y = 0 ------- (2)
Multiply eqn 1 with √8
We get,
4x + 2√6y = 0 ------ (3)
Multiply eqn 2 with √3
We get,
3x - 2√6y = 0 ------ (4)
Add eqn (3) & (4)
We get,
4x + 2√6y = 0 +
3x - 2√6y = 0
--------------------
7x = 0
Therefore x = 0
Substituting x in any above eqn we will get y = 0.