
Given that:
∠APB = 60∘,∠CPD = 30∘,AC = 80m
To find:
The height of the pole = AB = CD = ?
Let AB and CD be the two poles of equal height and P be the point on the road between the poles.

Adding eqn. (i) and eqn. (ii) we get,

Therefore, height of the pole = 20√3m = 34.64m