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A 50 ohm resistor is in parallel with 10 ohm resistor current in 50 ohm resistor is 7.2 Amps. How will you add a third resistor and what will be its value of the line current if the line current is to be 1.2 Amps.

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The current in 50Ω resistor is 7.2

v = iR

v = 7.2 x 50

v = 360 volt

100Ω resistance are parallel to 50Ω. In parallel voltage is same

\(I_2 = \frac VR\)

\(I_2 = \frac{360}{100}\)

\(I_2 = 3.6 A\)

Total current = 12.1 A

I1 + I2 + I3 = 12.1

7.2 + 3.6 + I3 = 12.1

I3 = 1.3A

Third resistance is also connected in parallel with 100Ω & 50Ω then

\(R = \frac{360}{1.3}\)

R = 276.9Ω

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