The current in 50Ω resistor is 7.2
v = iR
v = 7.2 x 50
v = 360 volt
100Ω resistance are parallel to 50Ω. In parallel voltage is same
\(I_2 = \frac VR\)
\(I_2 = \frac{360}{100}\)
\(I_2 = 3.6 A\)
Total current = 12.1 A
I1 + I2 + I3 = 12.1
7.2 + 3.6 + I3 = 12.1
I3 = 1.3A
Third resistance is also connected in parallel with 100Ω & 50Ω then
\(R = \frac{360}{1.3}\)
R = 276.9Ω