Correct option : (b) 997918
The common difference between the divisors and the respective remainders
\(= (6 - 4) = 7 - 5 = 8 - 6\)
\(=9-7=10-8=2\).
LCM of 6, 7, 8, 9 and 10 = 2520.
\(\therefore\) Required number is 2520k - 2.
Greatest number of six digits is 999999.
Now,
![](https://dk7h1f5gq849l.cloudfront.net/photos/questions/1-1677745292-3a9c8b32-f15d-4ac7-876e-e1cdcc2a8bc4.png)
\(\therefore\) k = 396
Hence, required number is \(2520\times 396 -2\)
\(=997920-2 =997918.\)