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Can I define a lambda function with optional arguments?

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Yes, you can define a lambda function with optional arguments in Python. 

You can use the standard syntax for defining a lambda function, and include default values for the optional arguments.

Here is an example:

# A lambda function with one required argument and one optional argument
my_lambda = lambda x, y=0: x + y

# Call the lambda function with one argument
result1 = my_lambda(5)
print(result1)  # Output: 5

# Call the lambda function with two arguments
result2 = my_lambda(5, 10)
print(result2)  # Output: 15
 

In this example, we define a lambda function called my_lambda with one required argument x and one optional argument y with a default value of 0.

When we call the lambda function with one argument (my_lambda(5)), the value of x is set to 5 and the value of y is set to the default value of 0. The lambda function returns the sum of x and y, which is 5 in this case.

When we call the lambda function with two arguments (my_lambda(5, 10)), the value of x is set to 5 and the value of y is set to 10. The lambda function returns the sum of x and y, which is 15 in this case.

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