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If ΔH f (H2O) is -286.20 kJ mol^-1, then ΔH°f (OH^-) is

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If ΔH f (H2O) is -286.20 kJ mol-1, then ΔH°f (OH-) is

(a) -228.88 kJ mol-1 

(b) + 228.88 kJ mol-1 

(c) -343.52 kJ mol-1 

(d) + 343.52 kJ mol-1

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Correct option (a) -228.88 kJmol-1   

Explanation:

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