Let 1/√x be ‘m’ and 1/√y be ‘n’,
Then the given equations become
2m + 3n = 2
4m - 9n = -1
( 2m + 3n = 2) X - 2
⇒ − 4m − 6n = − 4 …(1)
4m - 9n = -1
4m − 9n = − 1 …(2)
Adding (1) and (2)
We get −15n = − 5 ⇒ n = 1/3
Substituting n = 1/3 in 2m + 3n = 2, we get