Question

Shortest distance between lines \(\frac{x+1}{7}=\frac{y+1}{-6}=\frac{z+1}{1}\) and \(\frac{x-3}{1}=\frac{y-5}{-2}=\frac{z-3}{1}\) is

(1) √29 

(2) 2√29 

(3) 3√29 

(4) 4√29

Answer 1

Correct option is (2) 2√29

 

= 2√29