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in Equilibrium by (25 points)
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For a reversible reaction \( A(s) \rightleftharpoons 2 B(g)+C(g) \), if at \( T(K) \) equilibrium pressure is \( P \) then \( K_{p} \) will be

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\(A(s)\rightleftharpoons 2B(g)+C(g)\)

\(∴ K_p =\frac{P^2_B\times P_c}{1}\)

\(K_p=P^2_B \times P_c\)

Because A is in solid forms so that Its activity will be = 1

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