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Let x = x (y) be the solution of the differential equation 2(y + 2)loge (y + 2)dx + (x + 4 - 2loge (y + 2))dy = 0, y > -1 with x (e4 – 2) = 1. Then x (e9 – 2) is equal to

(1) 4/9 

(2) 10/3 

(3) 32/9 

(4) 3

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