Question

Calculate the e.m.f of a cell of Cu = 0.34 and the Zn = 0.764.

Answer 1

Zn → Zn⁺² + 2^e-

\(E^o_{0\times d}\) = 0.764

Or Zn⁺² + 2^e- → Zn

\(E^o_{red}\) = -0.764 — (i)

Cu⁺² + 2^e- → Cu

\(E^o_{red}\) = 0.34 V — (ii)

On substraction equation (i) & (ii) we get

Cu⁺² + Zn → Cu + Zn⁺²

E⁰ = 0.34 + 0.764

\(E^o_{cell}\) = 1.104 V