Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
2.4k views
in Mathematics by (76.5k points)

The part of straight line y = x between x = 1 and x = 2 is revolved about x-axis, then the curved surface area of the solid thus generated is

(a) 2√2π

(b) 3√2π

(c) 3√2π

(d) None of these

1 Answer

+1 vote
by (72.4k points)
selected by
 
Best answer

Correct option: (c) 3√2π

Explanation:

Curved surface area obtained on revolving a function between x = a and x = b along x-axis is:

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...