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n [1/(n + 1)(n + 2) + 1/(n + 2)(n + 4) + .....+ 1/6n2] where, lim(n→∞) is equal to  

(a) log (3/2)

(b) log (5/2)

(c) log (1/2)

(d) log (7/4)

1 Answer

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Best answer

Correct option: (a) log(3/2)

Explanation:

Taking n common from the denominator of the above limit we get

 

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