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2-Methyl propyl bromide reacts with C2H5O- and gives 'A' whereas on reaction with C2H5OH it gives 'B'. The mechanism followed in these reactions and the products 'A' and 'B' respectively are

(1) SN2. A iso-butyl ethyl ether; SN1, B = tert- butyl ethyl ether

(2) SN1, A = tert-butyl ethyl ether; SN1, B = 2- butyl ethyl ether

(3) SN1, A tert-butyl ethyl ether; SN2, B = iso- butyl ethyl ether

(4) SN2, A = 2-butyl ethyl ether; SN2, B = iso- butyl ethyl ether

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(1) SN2. A iso-butyl ethyl ether; SN1, B = tert- butyl ethyl ether

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