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in Mathematics by (69.1k points)

 Lines 5x + 12y –10 = 0 and 5x – 12y – 40 = 0 touch a circle C1 (of diameter 6). If centre of C1 lies in the first quadrant, find concentric circle C2 which cuts intercepts of length 8 units on each given line. 

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Consider centre of required circle is (h, k) and by using perpendicular distance formula from centre to given tangent we will get value of h and k

Let centre of circle C1 be O (h, k), where h > 0 and k > 0 

WP = 4 and OP = 3 … (given)

⇒ k = 2 (as k > 0)

Hence, equation of required circle is 

(x – 5)2 + (y – 2)2 = 25

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