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In a triangle ABC, if cos A + 2 cos B + cos C = 2 and the lengths of the sides opposite to the angles

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In a triangle ABC, if cos A + 2 cos B + cos C = 2 and the lengths of the sides opposite to the angles A and C are 3 and 7 respectively, then cos A – cos C is equal to 

(1) 3/7 

(2) 9/7 

(3) 10/7 

(4) 5/7

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Correct option is (3) 10/7

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