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If f(x)=\(\frac{x^2-4}{x-2}\) and g(x)=x+2, \(x \in \mathbb{R}\) , then which of the following is correct

(a)Both f and g are continuous at x=2

(b) Both f and g are discontinuous at x=2

(c)f is continuous at x=2 but g is discontinuous at x=2

(d)f is discontinuous at x=2 but g is continuous at x=2

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The correct answer is: (d) f is discontinuous at x=2 but g is continuous at x=2

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