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If three distinct natural numbers are chosen randomly from the first natural numbers, then the probability that all three of them

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If three distinct natural numbers are chosen randomly from the first natural numbers, then the probability that all three of them are divisible by both 2 and 3, is

(a) 4/25

(b) 4/35

(c) 4/1161

(d) 4/1155

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1 Answer

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Best answer

Correct option: (d) 4/1155

Explanation: 

A number is divisible by both 2 and 3 if it is divisible by 6.

The number divisible by 6 are 6, 12, 18,…96 = 16

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