The correct option (d) t = (1/600) sec
Explanation:
I = 2 sin[100πt + (π/3)]
Given current will be maximum. Here Imax is given to be 2A
∴ I = Imax = 2A
∴ 2 = 2 sin[100πt + (π/3)]
∴ 1 = sin[100πt + (π/3)]
∴ 100 πt (π/3) = (π/2)
100 πt = (π/6)
∴ t = (1/600) sec