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If I(x) = ∫esin\(^2\)x (cos x sin 2x - sin x)dx and I (0) = 1, then I(π/3) is equal to

(1) \(-\frac{1}{2}e^{\frac{3}{4}}\)

(2) \(e^{\frac{3}{4}}\)

(3) \(\frac{1}{2}e^{\frac{3}{4}}\)

(4) \(-e^{\frac{3}{4}}\)

1 Answer

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Best answer

 Correct option is (3) \(\frac{1}{2}e^{\frac{3}{4}}\)

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