Question

In a plane electromagnetic wave travelling in free space, the electric field component oscillates sinusoidally at a frequency of 2.0 × 10¹⁰ Hz and amplitude 48 Vm^-1. Then the amplitude of oscillating magnetic field is: (Speed of light in free space = 3 x 10⁸ ms^-1)

(1) 1.6 x 10^-8 T
(2) 1.6 x 10^-7 T
(3) 1.6 x 10^-6 T
(4) 1.6 x 10^-9 T

Answer 1

Correct option is (2) 1.6 x 10^-7 T

C = \(\frac{E_0}{B_0}\)

\(B_0\) = \(\frac{E_0}{C}\)

= \(\frac{48}{3\ \times\ 10^8}\)

= 1.6 x 10^-7 T