Question

The trajectory of projectile, projected from the ground is given by y = \(x-\frac{x^2}{20}\). Where x and y are measured in meter. The maximum height attained by the projectile will be

(1) 5 m 

(2) 10√2m 

(3) 200 m 

(4) 10 m

Answer 1

Correct option is (1) 5 m