Correct option is (3) [Fe(SCN)]2+
In case nitrogen and sulphur both are present in an organic compound, sodium thiocyanate is formed, it give blood red colour and no prussian blue since there are no free cyanide lons.
Na + C + N + S → NaSCN
Fe+3 + SCN\(^\Theta\) → [Fe(SCN)]2+ (Blood red)