Correct option is (d) –1
As given, (x + 1)(4x2 + 6x)(2x2 + 6x − 1)
= (4x3 + 6x2 + 4x2 + 6x)(2x2 + 6x − 1)
= (4x3 + 10x2 + 6x)(2x2 + 6x − 1)
= (8x5 + 24x4 − 4x3 + 20x4 + 60x3 − 10x2 + 12x3 + 36x2 − 6x)
Here there no constant term.
Thus, −1 is not a term of the polynomial.