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The value of the expression \(\frac{(x^2 - y^2)^3 + (y^2 - z^2)^3 + (z^2 - x^2)^3}{(x - y)^3 + (y - z)^3 + (z - x)^3}\) is

(a) (x2 - y2) (y2 - z2) (z2 - x2)

(b) 3(x - y) (y - z) (z - x)

(c) (x + y) (y + z) (z + x)

(d) 3(x + y) (y + z) (z + x)

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Best answer

Correct option is (c) (x + y) (y + z) (z + x)

Given,

\(\frac{(x^2 - y^2)^3 + (y^2 - z^2)^3 + (z^2 - x^2)^3}{(x - y)^3 + (y - z)^3 + (z - x)^3}\)

we have x2 − y2 + y2 − z2 + z2 − x2 = 0

∵ (x2 − y2)3 + (y2 − z2)3 + (z− x2)3 = 3(x− y2)(y− z2)(z2 − x2)

Similarly , (x − y)3 + (y − z)+ (z − x)3 = 3(x − y)(y − z)(z − x)

So, the given expression is

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