Correct option is (c) 76°
In trapezium ABCD, AB ∥ CD, AD = BC
Draw a perpendicular from A on CD to meet CD at M and a perpendicular from B on CD to meet at N.
Now, in △ADM and △BNC
∠AMD = ∠BNC (Each 90°)
AM = BN (distance between parallel lines)
AD = BC (Given)
Thus, △ADM ≅ △BCN (SAS rule)
Hence, ∠D = ∠C = 76∘ (by CPCT)