Correct option is (a) \(\frac{44}3\sqrt 3\) cm
Let △ABC be an equilateral triangle.
Length of each side be ′a′ cm
O is a point in the interior of the triangle .
OX ⊥ BC, OY ⊥ CA and OZ ⊥ AB
Let OZ = 6cm, OX = 7cm and OY = 9cm
Area of △ABC = Area of △AOB + Area of △BOC + Area of △COA
