Correct option is (c) (4, 2)
Centroid of a triangle = \(\left(\frac{x_1 + x_2 + x_3}{3}, \frac{y_1+y_2+y_3}3\right)\)
Let the third vertex of the triangle be (x, y)
So, centroid = \(\left(\frac{-4 + 0 + x}{3}, \frac{1 - 3 + y}3\right) = (0,0)\)
⇒ \(\left(\frac{-4 + x}3, \frac{-2 + y}3\right) = (0,0)\)
⇒ −4 + x = 0; −2 + y = 0
x = 4; y = 2
Hence, the third vertex of the triangle is (4, 2).