A→(r), B→(s), C→(p), D→(q)
[Co(NH3)6] Cl3 will give maximum number of ions(4) because of which conductivity is maximum i.e. 404.
In [Co(NH3) 3Cl3] no ions are given
Hence molar conductivity is zero.
[Co(NH3) 5Cl]Cl2 & [Co(NH3) 4Cl2] Cl forms 3 & 2 ions.