(1 + 2xy cosx2 − 2xy) dx + (sinx2 − x2) dy = 0
(1 + 2xy cos(x2) − 2xy) dx + (sin(x2) − x2) dy = 0
First order linear Ordinary Differential Equation
A first order linear ODE has the form of y′(x) + p(x)y = q(x)
Let y be the dependent variable, Divide by dx:
