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Let a and b be two nonzero real numbers. If the coefficient of x5 in the expansion of \(\left(ax^2 + \frac{70}{27bx}\right)^4\) is equal to the coefficient of x–5 in the expansion of \(\left(ax - \frac 1{bx^2}\right)^7\) , then the value of 2b is ______.

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