Question

Range of f(x) = sin^-1x + sec^-1x + tan^-1x is

(A) \(\left\{\frac{3\pi}4\right\}\)

(B) (-π, 2π)

(C) [-π, 2π]

(D) None of these

Answer 1

Correct option is (D) None of these

Domain of each inverse trigonometric term

So range of given function is \(\left\{\frac \pi 4, \frac{3\pi }4\right\}\).